\(1\frac{1}{3}x-\left(\frac{3}{2}\right)^2=-0,75\)
\(\frac{4}{3}x-\frac{9}{4}=-\frac{3}{4}\)
\(\frac{4}{3}x=-\frac{3}{4}+\frac{9}{4}\)
\(\frac{4}{3}x=\frac{3}{2}\)
\(x=\frac{3}{2}:\frac{4}{3}\)
\(x=\frac{3}{2}.\frac{3}{4}\)
\(x=\frac{9}{8}\)
Vậy \(x=\frac{9}{8}\)