\(\left(0,4x-1,3\right)^2=5,29\)
\(\left(0,4x-1,3\right)^2=\left(\pm2,3\right)^2\)
+) 0,4x - 1,3 = 2,3
0,4x = 3,6
x = 9
+) 0,4x - 1,3 = -2,3
0,4x = -1
x = -2,5
Vậy,........
(0,4x - 1,3)2 = 5,29
(0,4x - 1,3)2 = 2,32
=> \(\orbr{\begin{cases}0,4x-1,3=2,3\\0,4x-1,3=-2,3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}0,4x=3,6\\0,4x=-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-\frac{5}{2}\end{cases}}\)
\(\left(0,4x-1,3\right)^2=5,29\)
Ta xét 2th:
Th1: \(0,4x-1,3=\sqrt{5,29}\)
\(0,4x-1,3=\sqrt{5,29}+1,3\)
=> x = 9
Th2: \(0,4x-1,3=-\sqrt{5,29}\)
\(0,4x-1,3=-\sqrt{5,29}+1,3\)
=> x = -2,5
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-2,5\end{cases}}\)