a) \(4x^2-x-3=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{3}{4}\end{matrix}\right.\) \(\left(a+b+c=1\right)\)
b) \(x^2-x-6=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\) \(\left(S=1;P=-6\right)\)
c) \(x^2-5x+10=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\) \(\left(S=5;P=10\right)\)
d) \(8x^2-12x+3=0\) sửa lại \(8x^2-11x+3=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{3}{8}\end{matrix}\right.\) \(\left(a+b+c=0\right)\)
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