\(...A=\dfrac{4x^2}{x-2}+\dfrac{3}{x-2}-\dfrac{19}{x-2}\)
\(\Rightarrow A=\dfrac{4x^2+3-19}{x-2}=\dfrac{4x^2-16}{x-2}\)
\(\Rightarrow A=\dfrac{4\left(x^2-4\right)}{x-2}=\dfrac{4\left(x-2\right)\left(x+2\right)}{x-2}=4\left(x+2\right)\)
\(\Rightarrow\) Chọn C \(:4\left(x+2\right)\)