Question

Answer 1

bài 1

a)m_C4H10=nxM=0,15x58=8,7g

b)m_MgO=nxM=0,45x40=18g

c)m_Al(OH)3=nxM=0,25x78=19,5 g

bài 2

a)n_Cl2=\(\dfrac{m}{M}\)=\(\dfrac{17,75}{71}\)=0,25 mol

b)n_O3=\(\dfrac{m}{M}\)=\(\dfrac{60}{48}\)=1,25 mol

c)n_SO3=\(\dfrac{m}{M}\)=\(\dfrac{12}{80}\)=0,15 mol 

 

Answer 2

bài 3

a)M_A=\(\dfrac{m}{n}\)=\(\dfrac{12}{0,5}\)=24 g

b)M_B=\(\dfrac{m}{n}\)=\(\dfrac{73,5}{0,75}\)=98 g

bài 4 

a)V_C4H10=nx 24,79=0,1x 24,79=2,479 l

b)ko có mol à

c)V_Cl2=nx24,79=0,25x24,79=6,1975 l

 

\(\dfrac{m}{n}\)\(\dfrac{m}{n}\)