Question

Answer 1

a) Ta có:
\(B=\dfrac{2x}{x^2-5x}\Rightarrow B=\dfrac{2x}{x\left(x-5\right)}\Rightarrow B=\dfrac{2}{x-5}\)
Mà \(A=\dfrac{2}{x-5}\)
\(\Rightarrow A=B\)

b) Ta có:
\(D=\dfrac{2x^2-3x-2}{3\left(2x+1\right)}\Rightarrow D=\dfrac{2x^2-4x+x-2}{3\left(2x+1\right)}\Rightarrow D=\dfrac{2x\left(x-2\right)+\left(x-2\right)}{3\left(2x+1\right)}\Rightarrow D=\dfrac{\left(2x+1\right)\left(x-2\right)}{3\left(2x+1\right)}\Rightarrow D=\dfrac{x-2}{3}\)
Mà \(C=\dfrac{x-2}{3}\)
\(\Rightarrow C=D\)