a)(\(\dfrac{-2}{3}\)x2y2z)(3xy2z2)
=(\(\dfrac{-2}{3}\)x3)(x2.x)(y2.y2)(z.z2)=-2x3y4z3
b)(3x3y2-5x2y+12xy):3xy
=x2y-\(\dfrac{5}{3}\)x+4
c)x(y+2z-yz)+z(xy-2x)
=xy+2xz-xyz+xyz-2xz
=xy
d)(4x-1)(4x+1)-(4x-1)2
=(4x-1)(4x+1)-2(4x-1)
=4x(4x+1)-1(4x+1)-8x+2
=16x2+4x-4x-1-8x+2
=16x2-8x+1
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