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CX
29 tháng 10 lúc 19:58

a)(\(\dfrac{-2}{3}\)x2y2z)(3xy2z2)

=(\(\dfrac{-2}{3}\)x3)(x2.x)(y2.y2)(z.z2)=-2x3y4z3

b)(3x3y2-5x2y+12xy):3xy

=x2y-\(\dfrac{5}{3}\)x+4

c)x(y+2z-yz)+z(xy-2x)

=xy+2xz-xyz+xyz-2xz

=xy

d)(4x-1)(4x+1)-(4x-1)2

=(4x-1)(4x+1)-2(4x-1)

=4x(4x+1)-1(4x+1)-8x+2

=16x2+4x-4x-1-8x+2

=16x2-8x+1

 

 

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