Câu hỏi của tuấn phùng anh

\(c,\left(-\dfrac{3}{4}\right)^2:\left(\dfrac{-1}{4}\right)^2+9\cdot\left(-\dfrac{1}{9}\right)+\dfrac{3}{2}\)\(=\dfrac{9}{16}\cdot16-1+\dfrac{3}{2}\)\(=9+\dfrac{1}{2}=\dfrac{19}{2}\)\(---\)\(d,\sqrt{0,25}\cdot\left(-3\right)^3-\sqrt{\dfrac{1}{81}}:\left(-\dfrac{1}{3}\right)^3\)\(=0,5\cdot\left(-27\right)-\dfrac{1}{9}\cdot\left(-27\right)\)\(=\left(-27\right)\cdot\left(0,5-\dfrac{1}{9}\right)\)\(=\left(-27\right)\cdot\dfrac{7}{18}=-\dfrac{21}{2}\)Câu trả lời: \(c,\left(-\dfrac{3}{4}\right)^2:\left(\dfrac{-1}{4}\right)^2+9\cdot\left(-\dfrac{1}{9}\right)+\dfrac{3}{2}\)\(=\dfrac{9}{16}\cdot16-1+\dfrac{3}{2}\)\(=9+\dfrac{1}{2}=\dfrac{19}{2}\)\(---\)\(d,\sqrt{0,25}\cdot\left(-3\right)^3-\sqrt{\dfrac{1}{81}}:\left(-\dfrac{1}{3}\right)^3\)\(=0,5\cdot\left(-27\right)-\dfrac{1}{9}\cdot\left(-27\right)\)\(=\left(-27\right)\cdot\left(0,5-\dfrac{1}{9}\right)\)\(=\left(-27\right)\cdot\dfrac{7}{18}=-\dfrac{21}{2}\)