Câu hỏi của Sir Nghi

\(a,27^3:3^3=\left(3^3\right)^3:3^3=3^9:3^3=3^3=27\)\(b,\left(\dfrac{3}{5}\right)^{15}:\left(\dfrac{9}{25}\right)^5=\left(\dfrac{3}{5}\right)^{15}:\left[\left(\dfrac{3}{5}\right)^2\right]^5\)\(=\left(\dfrac{3}{5}\right)^{15}:\left(\dfrac{3}{5}\right)^{10}=\left(\dfrac{3}{5}\right)^5=\dfrac{243}{3125}\)\(c,\dfrac{20^5.5^{10}}{100^5}=\dfrac{20^5.5^{10}}{\left(20.5\right)^5}\)\(=\dfrac{20^5.5^{10}}{20^5.5^5}=5^5=3125\)Câu trả lời: \(a,27^3:3^3=\left(3^3\right)^3:3^3=3^9:3^3=3^3=27\)\(b,\left(\dfrac{3}{5}\right)^{15}:\left(\dfrac{9}{25}\right)^5=\left(\dfrac{3}{5}\right)^{15}:\left[\left(\dfrac{3}{5}\right)^2\right]^5\)\(=\left(\dfrac{3}{5}\right)^{15}:\left(\dfrac{3}{5}\right)^{10}=\left(\dfrac{3}{5}\right)^5=\dfrac{243}{3125}\)\(c,\dfrac{20^5.5^{10}}{100^5}=\dfrac{20^5.5^{10}}{\left(20.5\right)^5}\)\(=\dfrac{20^5.5^{10}}{20^5.5^5}=5^5=3125\)