Câu hỏi của Trần Khánh Ngọc

Question

⭐Hannie⭐ · Accepted Answer

`1,(x+1/2) xx 2/3=-5/7``=> x+1/2= -5/7 : 2/3``=>x+1/2=-5/7 xx 3/2``=> x+1/2= -15/14``=>x=-15/14-1/2``=>x=-15/14 - 7/14``=>x= -22/14``=>x=-11/7`__`2,(9/5-x)+1/2=-2/3``=> 9/5 -x =-2/3 -1/2``=> 9/5 -x= -4/6 -3/6``=> 9/5-x= -7/6``=> x= 9/5- (-7/6)``=>x=9/5 + 7/6``=>x=89/30`__`3,(5/6 xx x)-2 1/2=-7/3``=> 5/6 xx x =-7/3 + 5/2``=> 5/6 xx x = -14/6 + 15/6``=> 5/6 xx x = 1/6``=>x=1/6:5/6``=>x=1/6 xx 6/5``=>x=6/30``=>x=1/5`__`4,(x- (-1)/3 )+3/4=-5/2``=> x+1/3=-5/2-3/4``=>x+1/3= -10/4-3/4``=>x+1/3= -13/4``=>x=-13/4-1/3``=>x=-43/12`__`5,(6/7 +x)-9/5=-2/10``=> 6/7 +x=-2/10+9/5``=>6/7+x=-2/10 + 18/10``=> 6/7 +x= 16/10``=>x= 8/5 -6/7``=>x=26/35`__`6,2 1/2` hay j vậy cậu nhỉ ?__`7,-9/10 -x=1/2 +(-7/5)``=> -9/10-x= 5/10 + (-14/10)``=> -9/10 -x= -9/10``=> x= -9/10 - (-9/10)``=>x= -9/10 + 9/10``=> x= 0`Câu trả lời: `1,(x+1/2) xx 2/3=-5/7``=> x+1/2= -5/7 : 2/3``=>x+1/2=-5/7 xx 3/2``=> x+1/2= -15/14``=>x=-15/14-1/2``=>x=-15/14 - 7/14``=>x= -22/14``=>x=-11/7`__`2,(9/5-x)+1/2=-2/3``=> 9/5 -x =-2/3 -1/2``=> 9/5 -x= -4/6 -3/6``=> 9/5-x= -7/6``=> x= 9/5- (-7/6)``=>x=9/5 + 7/6``=>x=89/30`__`3,(5/6 xx x)-2 1/2=-7/3``=> 5/6 xx x =-7/3 + 5/2``=> 5/6 xx x = -14/6 + 15/6``=> 5/6 xx x = 1/6``=>x=1/6:5/6``=>x=1/6 xx 6/5``=>x=6/30``=>x=1/5`__`4,(x- (-1)/3 )+3/4=-5/2``=> x+1/3=-5/2-3/4``=>x+1/3= -10/4-3/4``=>x+1/3= -13/4``=>x=-13/4-1/3``=>x=-43/12`__`5,(6/7 +x)-9/5=-2/10``=> 6/7 +x=-2/10+9/5``=>6/7+x=-2/10 + 18/10``=> 6/7 +x= 16/10``=>x= 8/5 -6/7``=>x=26/35`__`6,2 1/2` hay j vậy cậu nhỉ ?__`7,-9/10 -x=1/2 +(-7/5)``=> -9/10-x= 5/10 + (-14/10)``=> -9/10 -x= -9/10``=> x= -9/10 - (-9/10)``=>x= -9/10 + 9/10``=> x= 0`

Vũ Quang Huy · Answer

$1,\left(x+\dfrac{1}{2}\right).\dfrac{2}{3}=\dfrac{-5}{7}$$x+\dfrac{1}{2}=\dfrac{-5}{7}:\dfrac{2}{3}$$x+\dfrac{1}{2}=\dfrac{-5}{7}.\dfrac{3}{2}$$x+\dfrac{1}{2}=\dfrac{-15}{14}$$x=\dfrac{-15}{14}-\dfrac{1}{2}$$x=\dfrac{-15}{14}+\dfrac{-7}{14}$$x=\dfrac{-11}{7}$$2,\left(\dfrac{9}{5}-x\right)+\dfrac{1}{2}=\dfrac{-2}{3}$     $\dfrac{9}{5}-x=\dfrac{-2}{3}-\dfrac{1}{2}$$\dfrac{9}{5}-x=\dfrac{-4}{6}+\dfrac{-3}{6}$$\dfrac{9}{5}-x=\dfrac{-7}{6}$$x=\dfrac{9}{5}-\dfrac{-7}{6}$$x=\dfrac{54}{30}-\dfrac{-35}{30}$$x=\dfrac{19}{30}$$3,\left(\dfrac{5}{6}.x\right)-2\dfrac{1}{2}=\dfrac{-7}{3}$      $\left(\dfrac{5}{6}.x\right)-\dfrac{5}{4}=-\dfrac{7}{3}$ $\dfrac{5}{6}.x=\dfrac{-7}{6}+\dfrac{5}{4}$$\dfrac{5}{6}.x=\dfrac{-28}{24}+\dfrac{30}{24}$$\dfrac{5}{6}.x=\dfrac{1}{12}$ $x=\dfrac{1}{12}:\dfrac{5}{6}$$x=\dfrac{1}{12}.\dfrac{6}{5}$$x=\dfrac{1}{10}$$4,\left(x-\dfrac{-1}{3}\right)+\dfrac{3}{4}=-\dfrac{5}{2}$       $x-\dfrac{-1}{3}=\dfrac{-5}{2}-\dfrac{3}{4}$$x-\dfrac{-1}{3}=\dfrac{-10}{4}+\dfrac{-3}{4}$$x-\dfrac{-1}{3}=\dfrac{-13}{4}$$x=\dfrac{-13}{4}+\dfrac{-1}{3}$$x=\dfrac{-39}{12}+\dfrac{-4}{12}$$x=\dfrac{-43}{12}$$5,\left(\dfrac{6}{7}+x\right)-\dfrac{9}{5}=\dfrac{-2}{10}$    $\dfrac{6}{7}+x=\dfrac{-2}{10}+\dfrac{9}{5}$$\dfrac{6}{7}+x=\dfrac{-2}{10}+\dfrac{18}{10}$$\dfrac{6}{7}+x=\dfrac{8}{5}$$x=\dfrac{8}{5}-\dfrac{6}{7}$$x=\dfrac{56}{35}-\dfrac{30}{35}$$x=\dfrac{26}{35}$  Câu trả lời: $1,\left(x+\dfrac{1}{2}\right).\dfrac{2}{3}=\dfrac{-5}{7}$$x+\dfrac{1}{2}=\dfrac{-5}{7}:\dfrac{2}{3}$$x+\dfrac{1}{2}=\dfrac{-5}{7}.\dfrac{3}{2}$$x+\dfrac{1}{2}=\dfrac{-15}{14}$$x=\dfrac{-15}{14}-\dfrac{1}{2}$$x=\dfrac{-15}{14}+\dfrac{-7}{14}$$x=\dfrac{-11}{7}$$2,\left(\dfrac{9}{5}-x\right)+\dfrac{1}{2}=\dfrac{-2}{3}$     $\dfrac{9}{5}-x=\dfrac{-2}{3}-\dfrac{1}{2}$$\dfrac{9}{5}-x=\dfrac{-4}{6}+\dfrac{-3}{6}$$\dfrac{9}{5}-x=\dfrac{-7}{6}$$x=\dfrac{9}{5}-\dfrac{-7}{6}$$x=\dfrac{54}{30}-\dfrac{-35}{30}$$x=\dfrac{19}{30}$$3,\left(\dfrac{5}{6}.x\right)-2\dfrac{1}{2}=\dfrac{-7}{3}$      $\left(\dfrac{5}{6}.x\right)-\dfrac{5}{4}=-\dfrac{7}{3}$ $\dfrac{5}{6}.x=\dfrac{-7}{6}+\dfrac{5}{4}$$\dfrac{5}{6}.x=\dfrac{-28}{24}+\dfrac{30}{24}$$\dfrac{5}{6}.x=\dfrac{1}{12}$ $x=\dfrac{1}{12}:\dfrac{5}{6}$$x=\dfrac{1}{12}.\dfrac{6}{5}$$x=\dfrac{1}{10}$$4,\left(x-\dfrac{-1}{3}\right)+\dfrac{3}{4}=-\dfrac{5}{2}$       $x-\dfrac{-1}{3}=\dfrac{-5}{2}-\dfrac{3}{4}$$x-\dfrac{-1}{3}=\dfrac{-10}{4}+\dfrac{-3}{4}$$x-\dfrac{-1}{3}=\dfrac{-13}{4}$$x=\dfrac{-13}{4}+\dfrac{-1}{3}$$x=\dfrac{-39}{12}+\dfrac{-4}{12}$$x=\dfrac{-43}{12}$$5,\left(\dfrac{6}{7}+x\right)-\dfrac{9}{5}=\dfrac{-2}{10}$    $\dfrac{6}{7}+x=\dfrac{-2}{10}+\dfrac{9}{5}$$\dfrac{6}{7}+x=\dfrac{-2}{10}+\dfrac{18}{10}$$\dfrac{6}{7}+x=\dfrac{8}{5}$$x=\dfrac{8}{5}-\dfrac{6}{7}$$x=\dfrac{56}{35}-\dfrac{30}{35}$$x=\dfrac{26}{35}$

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