\(a,R_{tđ}=R_1+R_2=8+10=18\Omega\)
\(U_{AB}=R_{tđ}.I=18.2=36\left(V\right)\)
\(b,R_3=R_1.2=8.2=16\Omega\)
\(R_{tđ}=\dfrac{16.18}{16+18}=\dfrac{144}{17}\Omega\)
\(U_{AB}=R_{tđ}.I=\dfrac{144}{17}.2=\dfrac{288}{17}\approx16,9\left(V\right)\)
\(I_1=\dfrac{U_{AB}}{R_1}=\dfrac{16,9}{8}=2,1125\left(A\right)\)
\(U_1+U_2=16,9V\)
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