\(2+\dfrac{x-5}{4}=\dfrac{4x-1}{6}\)
\(\Leftrightarrow\dfrac{2.12}{1.12}\dfrac{\left(x-5\right)3}{4.3}=\dfrac{\left(4x-1\right).2}{6.2}\)
\(\Leftrightarrow24+3x-15=8x-2\)
\(\Leftrightarrow3x-8x=-2-24+15\)
\(\Leftrightarrow-5x=-11\)
\(\Leftrightarrow x=\dfrac{11}{5}\)
\(2+\dfrac{x-5}{4}=\dfrac{4x-1}{6}\)
\(\Leftrightarrow2+\dfrac{x-5}{4}-\dfrac{4x-1}{6}=0\)
\(\Leftrightarrow\dfrac{2.12+3\left(x-5\right)-2\left(4x-1\right)}{12}=0\)
\(\Leftrightarrow24+3x-15-8x+2=0\)
\(\Leftrightarrow-5x=-11\)
\(\Leftrightarrow x=\dfrac{11}{5}\)
\(2+\dfrac{x-5}{4}=\dfrac{4x-1}{6}\)
\(\Leftrightarrow\dfrac{24}{12}+\dfrac{3\left(x-5\right)}{12}=\dfrac{2\left(4x-1\right)}{12}\)
\(\Leftrightarrow24+3x-15=8x-2\)
\(\Leftrightarrow3x+9=8x-2\)
\(\Leftrightarrow3x-8x=-9-2\)
\(\Leftrightarrow-5x=-11\)
\(\Leftrightarrow x=\dfrac{11}{5}\)
\(\text{Vậy phương trình có tập nghiệm là }S=\left\{\dfrac{11}{5}\right\}\)
