nMg = 6/24 = 0.25 (mol)
Mg + 2HCl => MgCl2 + H2
0.25....................0.25....0.25
VH2 = 0.25*22.4 = 5.6 (l)
mMgCl2 = 0.25*95 = 23.75 (g)
a) nMg=0,25(mol)
PTHH: Mg + 2 HCl -> MgCl2 + H2
0,25_______________0,25___0,25(mol)
V(H2,ddktc)=0,25.22,4=5,6(l)
b) mMgCl2=0,25. 95=23,75(g)