a)
\(\left(2x+3\right)\left(x-2\right)-2x\left(x-8\right)=24\)
\(2x^2-4x+3x-6-2x^2+16x=24\)
\(2x^2-2x^2-4x+3x+16x-6=24\)
\(15x-6=24\\ 15x=24+6\\ 15x=30\\ x=30:15\\ x=2\)
b)
\(5x\left(x-3\right)-x+3=0\\ 5x\left(x-3\right)-\left(x-3\right)=0\\ \left(x-3\right)\left(5x-1\right)=0\\ \left[{}\begin{matrix}x-3=0\\5x-1=0\end{matrix}\right.\left[{}\begin{matrix}x=3\\x=\dfrac{1}{5}\end{matrix}\right.\)
a/
\(\left(2x+3\right)\left(x-2\right)-2x\left(x-8\right)=24\\ \Leftrightarrow2x^2-4x+3x-6-2x^2+16x=24\\ \Leftrightarrow15x=30\\ \Leftrightarrow x=2\)
b/
\(5x\left(x-3\right)-x+3=0\\ \Leftrightarrow5x^2-15x-x+3=0\\ \Leftrightarrow5x^2-16x+3=0\\ \Leftrightarrow x\left(5x-16\right)=-3\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\5x-16=-3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{13}{5}\end{matrix}\right.\)
