Question

Answer 1

\(M_X=16,25.2=32,5g/mol\)

gọi: \(\left\{{}\begin{matrix}n_{N_2}=x\\n_{NO_2}=y\end{matrix}\right.\)

ta có: \(M_X=\dfrac{m_X}{n_X}=\dfrac{28x+46y}{x+y}=32,5\)

<=> \(32,5\left(x+y\right)=28x+46y\)

<=> \(32,5x+32,5y-28x-46y=0\)

<=> \(4,5x=13,5y\)

=> \(\dfrac{x}{y}=\dfrac{13,5}{4,5}=3\)

<=> x = 3y

=> \(\%V_{N_2}=\%n_{N_2}=\dfrac{x.100}{x+y}=\dfrac{3y.100}{3y+y}=\dfrac{300y}{4y}=75\%\)

=> \(\%V_{NO_2}=\%n_{NO_2}=100-75=25\%\)