Bài 11:
1 tấn = 1000 (kg)
Ta có: \(m_{CaCO_3}=1000.80\%=800\left(g\right)\)
\(\Rightarrow n_{CaCO_3}=\dfrac{800}{100}=8\left(kmol\right)\)
PT: \(CaCO_3\underrightarrow{t^o}CaO+CO_2\)
_____8______8 (kmol)
\(\Rightarrow m_{CaO\left(LT\right)}=8.56=448\left(kg\right)\)
Mà: H% = 90% \(\Rightarrow m_{CaO\left(TT\right)}=448.90\%=403,2\left(kg\right)\)
Bài 12:
Ta có: \(n_{CaO}=\dfrac{11,2}{56}=0,2\left(kmol\right)\)
PT: \(CaCO_3\underrightarrow{t^o}CaO+CO_2\)
____0,2_____0,2 (mol)
\(\Rightarrow m_{CaCO_3\left(LT\right)}=0,2.100=20\left(kg\right)\)
Mà: H% = 70% \(\Rightarrow m_{CaCO_3\left(TT\right)}=\dfrac{20}{70\%}=\dfrac{200}{7}\left(kg\right)\)
\(\Rightarrow m_{đavoi}=\dfrac{\dfrac{200}{7}}{85\%}\approx33,61\left(kg\right)\)