Lời giải:
\(\frac{(-5)^{32}.(2^2.5)^{43}}{[(-2)^3]^{29}.(5^3)^{25}}=\frac{-5^{32}.2^{86}.5^{43}}{-2^{87}.5^{75}}=\frac{-2^{86}.5^{75}}{-2^{87}.5^{75}}=\frac{1}{2}\)
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