H24
22 tháng 6 2022 lúc 21:02

a) \(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{3}{4}\right)\le x\le\dfrac{1}{24}-\left(\dfrac{1}{8}-\dfrac{1}{3}\right)\)

\(\dfrac{6}{12}-\left(\dfrac{4}{12}+\dfrac{9}{12}\right)\le x\le\dfrac{1}{24}-\left(\dfrac{3}{24}-\dfrac{8}{24}\right)\)

\(\dfrac{6}{12}-\dfrac{13}{12}\le x\le\dfrac{1}{24}-\left(-\dfrac{5}{24}\right)\)

\(-\dfrac{7}{12}\le x\le\dfrac{1}{4}\)

b) Làm rồi :vvv

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MH
22 tháng 6 2022 lúc 21:04

a) \(-\dfrac{7}{12}\le x\le\dfrac{3}{12}\)

\(x\in\left\{-\dfrac{7}{12};-\dfrac{6}{12};...;\dfrac{3}{12}\right\}\)

b) \(-\dfrac{1}{12}< x< \dfrac{1}{8}\)

\(\Leftrightarrow-\dfrac{2}{24}< x< \dfrac{3}{24}\)

\(x\in\left\{-\dfrac{1}{24};...;\dfrac{2}{24}\right\}\)

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