a, PT: \(Zn+2HCl\rightarrow ZnCl_2+H_2\)
b, Ta có: \(n_{Zn}=\dfrac{26}{65}=0,4\left(mol\right)\)
Theo PT: \(n_{H_2}=n_{Zn}=0,4\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,4.22,4=8,96\left(l\right)\)
PT: \(2H_2+O_2\underrightarrow{t^o}2H_2O\)
Theo PT: \(n_{H_2O}=n_{H_2}=0,4\left(mol\right)\)
\(\Rightarrow m_{H_2O}=0,4.18=7,2\left(g\right)\)
Bạn tham khảo nhé!
Đúng 1
Bình luận (0)