Question

Answer 1

C7:

Ta có: \(tanC=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{tanC}=\dfrac{2}{tan30^o}=2:\dfrac{1}{\sqrt{2}}=2\sqrt{2}\left(cm\right)\)

=> S ABC = \(\dfrac{1}{2}.AB.AC=\dfrac{1}{2}.2.2\sqrt{2}=2\sqrt{2}\left(cm^2\right)\)

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