Question

Answer 1

`a)PTHH:`

`Zn + 2HCl -> ZnCl_2 + H_2↑`

`0,03` `0,06`       `0,03`     `0,03`    `(mol)`

`n_[Zn] = [ 1,95 ] / 65 = 0,03 (mol)`

`=> V_[H_2] = 0,03 . 22,4 = 0,672 (l)`

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`b) m_[dd HCl] = [ 0,06 . 36,5 ] / [ 7,3 ] . 100 = 30 (g)`

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`c) ZnCl_2:` Kẽm clorua

  `C%_[ZnCl_2] = [ 0,03 . 136 ] / [ 1,95 + 30 - 0,03 . 2 ] . 100 ~~ 12,79 %`