Question

Answer 1

\(\lim\dfrac{n^3-3n^2+2}{n^4+3n^3+1}=\lim\dfrac{\dfrac{1}{n}-\dfrac{3}{n^2}+\dfrac{2}{n^4}}{1+\dfrac{3}{n}+\dfrac{1}{n^4}}=\dfrac{0}{1}=0\)