\(\dfrac{x+15}{88}=\dfrac{23}{8}\)
\(x+15=\dfrac{23}{8}\times88\)
\(x+15=253\)
\(x=253-15\)
\(x=238\)
\(\dfrac{x+15}{88}=\dfrac{23.11}{8.11}\)
khử mẫu
x+15=253
x=253-15
x=238
\(\text{x+1588=238x+1588=238 x+15=238×88x+15=238×88 x+15=253x+15=253 x=253−15x=253−15 x=238}\)
Quy đồng: \(\dfrac{23}{8}=\dfrac{23x11}{8x11}=\dfrac{253}{88}\)
Sau đó ta biết \(\dfrac{253-15}{88}=\dfrac{238}{88}\)
Vậy số cần điền là: 238