\(\dfrac{x-1}{x+2}-\dfrac{x}{x-2}=\dfrac{7x-6}{4-x^2}\)(đkxđ:\(x\ne\pm2\))
\(\Leftrightarrow\dfrac{x-1}{2+x}+\dfrac{x}{2-x}=\dfrac{7x-6}{\left(2-x\right)\left(2+x\right)}\)
\(\Leftrightarrow\dfrac{\left(x-1\right)\left(2-x\right)}{\left(2+x\right)\left(2-x\right)}+\dfrac{x\left(2+x\right)}{\left(2+x\right)\left(2-x\right)}=\dfrac{7x-6}{\left(2+x\right)\left(2-x\right)}\)
\(\Rightarrow\left(x-1\right)\left(2-x\right)+x\left(2+x\right)=7x-6\)
\(\Leftrightarrow2x-x^2-2+x+2x+x^2=7x-6\)
\(\Leftrightarrow2x+x+2x-7x=-6+2\)
\(\Leftrightarrow-2x=-4\)
\(\Leftrightarrow x=2\)(ko tm)
Vậy pt trên vô nghiệm.
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giúp em với ạ 🥺🥺em cầu xin lun
