Question

Answer 1

đk : x khác 0 ; -3 ; 3 

\(A=\left(\dfrac{\left(3-x\right)\left(x+3\right)^2}{\left(x+3\right)^2\left(x-3\right)}+\dfrac{x}{x+3}\right):\dfrac{3x^2}{x+3}\)

\(=\left(\dfrac{-x-3+x}{x+3}\right):\dfrac{3x^2}{x+3}=\dfrac{-3}{3x^2}=-\dfrac{1}{x^2}\)

 

Answer 2

Yêu cầu đề bài là gì bạn cần ghi chú rõ ra.

Answer 3

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