a) \(x+\dfrac{1}{2}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}-\dfrac{1}{2}\)
\(x=1\)
b) \(\dfrac{2}{3}\cdot x+\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}\cdot x=\dfrac{1}{10}-\dfrac{1}{2}\)
\(\dfrac{2}{3}\cdot x=-\dfrac{2}{5}\)
\(x=-\dfrac{2}{5}\div\dfrac{2}{3}\)
\(x=-\dfrac{3}{5}\)
c) \(\dfrac{x}{42}=\dfrac{-15}{21}\)
\(x=\dfrac{\left(-15\right)\cdot42}{21}\)
\(x=-30\)
d) \(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right)\div\left(2+\dfrac{1}{6}-\dfrac{1}{4}\right)=\dfrac{7}{46}\)
\(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right)\div\dfrac{23}{12}=\dfrac{7}{46}\)
\(x+\dfrac{-1}{12}=\dfrac{7}{46}\cdot\dfrac{23}{12}\)
\(x-\dfrac{1}{12}=\dfrac{7}{24}\)
\(x=\dfrac{7}{24}+\dfrac{1}{12}\)
\(x=\dfrac{7}{24}+\dfrac{2}{24}\)
\(x=\dfrac{9}{24}=\dfrac{3}{8}\)
a) \(x+\dfrac{1}{2}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}-\dfrac{1}{2}\)
\(x=1\)
vậy x =...
b) \(\dfrac{2}{3}.x+\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}.x=\dfrac{1}{10}-\dfrac{1}{2}\)
\(\dfrac{2}{3}.x=\dfrac{-2}{5}\)
\(x=\dfrac{-2}{5}:\dfrac{2}{3}\)
\(x=\dfrac{-3}{5}\)
vậy x =...