\(\left(3x-1\right)^2-\left(x+3\right)\left(2x-1\right)=7\left(x+1\right)\left(x-2\right)-3x\\ \Leftrightarrow9x^2-6x+1-\left(2x^2+5x-3\right)=7\left(x^2-x-2\right)-3x\\ \Leftrightarrow9x^2-6x+1-2x^2-5x+3=7x^2-7x-14-3x\)
\(\Leftrightarrow7x^2-11x+4=7x^2-10x-14\\ \Leftrightarrow x-18=0\\ \Leftrightarrow x=18\)