a.Ta có:
\(\dfrac{MD}{ED}=\dfrac{4}{12}=\dfrac{1}{3};\dfrac{ND}{FD}=\dfrac{5}{15}=\dfrac{1}{3}\)
=> MN//EF ( Ta-lét đảo )
b. ta có: MN//EF(cmt)
\(\Rightarrow\dfrac{MN}{EF}=\dfrac{DM}{DE}=\dfrac{DN}{DF}\)
\(\Leftrightarrow\dfrac{8}{EF}=\dfrac{1}{3}\)
\(\Leftrightarrow EF=24cm\)
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