\(c,\dfrac{5}{6}+\dfrac{5}{9}-\dfrac{1}{4}=\dfrac{30}{36}+\dfrac{20}{36}-\dfrac{9}{36}=\dfrac{41}{36}\\ d,\dfrac{9}{10}-\left(\dfrac{2}{5}+\dfrac{3}{10}\right)=\dfrac{9}{10}-\left(\dfrac{4}{10}+\dfrac{3}{10}\right)=\dfrac{9}{10}-\dfrac{7}{10}=\dfrac{2}{10}=\dfrac{1}{5}\)
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