\(\lim\dfrac{n}{n^2+2n-5}=\lim\dfrac{\dfrac{1}{n}}{1+\dfrac{2}{n}-\dfrac{5}{n^2}}=\dfrac{0}{1+0-0}=0\)
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\(\lim\dfrac{n}{n^2+2n-5}=\lim\dfrac{\dfrac{1}{n}}{1+\dfrac{2}{n}-\dfrac{5}{n^2}}=\dfrac{0}{1+0-0}=0\)