Question

Answer 1

5)

\(n_{CO_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)

\(n_{NaOH}=0,15.1=0,15\left(mol\right)\)

PTHH: 2NaOH + CO₂ --> Na₂CO₃ + H₂O

            0,15--->0,075----->0,075

             Na₂CO₃ + CO₂ + H₂O --> 2NaHCO₃

           0,025<----0,025-------------->0,05

=> \(\left\{{}\begin{matrix}n_{Na_2CO_3}=0,05\left(mol\right)\\n_{NaHCO_3}=0,05\left(mol\right)\end{matrix}\right.\)

6)

\(n_{CO_2}=\dfrac{11,2}{22,4}=0,5\left(mol\right)\)

\(n_{KOH}=0,6.1,5=0,9\left(mol\right)\)

PTHH: 2KOH + CO₂ --> K₂CO₃ + H₂O

             0,9---->0,45---->0,45

            K₂CO₃ + CO₂ + H₂O --> 2KHCO₃

             0,05<---0,05--------------->0,1

=> \(\left\{{}\begin{matrix}n_{K_2CO_3}=0,4\left(mol\right)\\n_{KHCO_3}=0,1\left(mol\right)\end{matrix}\right.\)

Answer 2

Answer 3