Question

Answer 1

Khí clo: Cl₂

Phân tử khối: 35,5.2 = 71 (đvC)

Axit cacbonic: H₂CO₃

Phân tử khối: 2.1 + 12 + 16.3 = 62 (đvC)

Answer 2

Khí clo : \(Cl_2\)

\(PTK_{Cl}=35.2=70\left(đvC\right)\)

Axit cacbonic : \(H_2CO_3\)

\(PTK_{H_2CO_3}=1.2+12+16.3=62\left(đvC\right)\)