\(PTHH:CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
\(V_{CH_4\left(pư\right)}=V_{CH_4\left(tổng\right)}.\left(100\%-25\%\right)=67,2.75\%=50,4\left(l\right)\\ n_{CH_4}=\dfrac{V_{\left(đktc\right)}}{22,4}=\dfrac{50,4}{22,4}=2,25\left(l\right)\)
\(Theo.PTHH:n_{O_2}=2.n_{CH_4}=2.2,25=4,5\left(l\right)\\ V_{O_2\left(đktc\right)}=n.22,4=4,5.22,4=100,8\left(l\right)\)
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