a, PTHH: 2Al + 6HCl \(\rightarrow\)2AlCl3 + 3H2
b, \(n_{Al}=\dfrac{5,4}{27}=0,2mol\)
\(\Rightarrow V_{H_2}=0,3.22,4=6,72l\)
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a, PTHH: 2Al + 6HCl \(\rightarrow\)2AlCl3 + 3H2
b, \(n_{Al}=\dfrac{5,4}{27}=0,2mol\)
\(\Rightarrow V_{H_2}=0,3.22,4=6,72l\)