Question

Answer 1

\(6NaOH+Fe_2\left(SO_{\text{4 }}\right)_3\rightarrow2Fe\left(OH\right)_3+3NaSO_4\)

Mg + 2AgNO\(_3\) → Mg(NO3)\(_2\) + 2Ag

4Na + O\(_2\) → 2Na\(_2\)O

2Al + 6HCl → 2AlCl\(_3\) + 3H\(_2\)

c2 a

\(mFe_3O_4=0,05.232=11,6g\)

b,

\(nSO_2=2,24:22,4=0,1mol\)

\(mSO_2=0,1.64=6,4g\)

c3 khong thấy đc

Answer 2

Bài 1 :

1) 6NaOH + Fe₂(SO₄)₃ -> 2Fe(OH)₃ + 3Na₂SO₄

2) Mg + 2AgNO₃ -> Mg(NO₃)₂ + 2Ag

3) Na + O₂ -> NaO₂

4) 2Al + 6HCl -> 2AlCl₃ + 3H₂

 

Answer 3

Bài 2 : 

a) \(m=n.M=0,05.232=11,6\left(g\right)\)

b) \(n=\dfrac{V}{22,4}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)

\(m=n.M=0,1.64=6,4\left(g\right)\)