\(a,\dfrac{x^2-10x+25}{x^2-5x}=\dfrac{\left(x-5\right)^2}{x\left(x-5\right)}=\dfrac{x-5}{x}\)
\(b,\dfrac{x}{2\left(x-1\right)}+\dfrac{x-2}{x^2-1}-\dfrac{5}{2x+2}\\ =\dfrac{x}{2\left(x-1\right)}+\dfrac{x-2}{\left(x-1\right)\left(x+1\right)}-\dfrac{5}{2\left(x+1\right)}\\ =\dfrac{x\left(x+1\right)}{2\left(x-1\right)\left(x+1\right)}+\dfrac{2\left(x-2\right)}{2\left(x-1\right)\left(x+1\right)}-\dfrac{5\left(x-1\right)}{2\left(x-1\right)\left(x+1\right)}\\ =\dfrac{x^2+x}{2\left(x-1\right)\left(x+1\right)}+\dfrac{2x-4}{2\left(x-1\right)\left(x+1\right)}-\dfrac{5x-5}{2\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x^2+x+2x-4-5x+5}{2\left(x-1\right)\left(x+1\right)}\\ =\dfrac{x^2-2x+1}{2\left(x-1\right)\left(x+1\right)}\\ =\dfrac{\left(x-1\right)^2}{2\left(x-1\right)\left(x+1\right)}\\ =\dfrac{x-1}{2\left(x+1\right)}\)
a,x2-2.5x+52 phần x(x-5)=(x-5)2 phần x(x-5)=x-5 phần x
phần b thì mik hơi lười nên ko lm tick cho mik nha
