Question

Answer 1

Câu 1: 

a, \(\%m_{Na}=\dfrac{46.100\%}{106}=43,39\%\)

\(\%m_C=\dfrac{12.100\%}{106}=11,32\%\)

\(\Rightarrow\%m_O=100\%-43,39\%-11,32\%=45,29\%\)

b, \(\%m_{Ba}=\dfrac{137.100\%}{208}=65,86\%\)

\(\Rightarrow\%m_{Cl}=100\%-65,86\%=34,14\%\)

Answer 2

Câu 2: 

a, \(V_{N_2}=\left(\dfrac{14}{14}\right).22,4=22,4l\)

b, \(V_{NH_3}=\left(\dfrac{32}{17}\right).22,4=42,112l\)

c, \(V_{Fe}=\left(\dfrac{6,5}{56}\right).22,4=2,688l\)

d, \(V_{CO_2}=\left(\dfrac{11}{44}\right).22,4=5,6l\)