Câu hỏi của Trang Tong thi

Bài 3:\(n_{H_2}=\dfrac{1,792}{22,4}=0,08\left(mol\right)\)PTHH: Zn + 2HCl --> ZnCl2 + H2_____a--------------------------->aMg + 2HCl --> MgCl2 + H2b--------------------------->b=> \(\left\{{}\begin{matrix}65a+24b=3,56\\a+b=0,08\end{matrix}\right.=>\left\{{}\begin{matrix}a=0,04\\b=0,04\end{matrix}\right.\)=> \(\left\{{}\begin{matrix}\%Zn=\dfrac{0,04.65}{3,56}.100\%=73,034\%\\\%Mg=\dfrac{0,04.24}{3,56}.100\%=26,966\%\end{matrix}\right.\) Câu trả lời: Bài 3:\(n_{H_2}=\dfrac{1,792}{22,4}=0,08\left(mol\right)\)PTHH: Zn + 2HCl --> ZnCl2 + H2_____a--------------------------->aMg + 2HCl --> MgCl2 + H2b--------------------------->b=> \(\left\{{}\begin{matrix}65a+24b=3,56\\a+b=0,08\end{matrix}\right.=>\left\{{}\begin{matrix}a=0,04\\b=0,04\end{matrix}\right.\)=> \(\left\{{}\begin{matrix}\%Zn=\dfrac{0,04.65}{3,56}.100\%=73,034\%\\\%Mg=\dfrac{0,04.24}{3,56}.100\%=26,966\%\end{matrix}\right.\)