Question

Answer 1

a) Zn + H₂SO₄ --> ZnSO₄ + H₂

b) \(n_{H_2}=\dfrac{2,479}{22,4}=\dfrac{2479}{22400}\)

PTHH: Zn + H₂SO₄ --> ZnSO₄ + H₂

___\(\dfrac{2479}{22400}\)<------------------------\(\dfrac{2479}{22400}\)

=> m_Zn = \(\dfrac{2479}{22400}.65=7,1935\left(g\right)\)

=> m_Cu = 10,5 - 7,1935 = 3,3065 (g)

c) Zn + CuSO₄ --> ZnSO₄ + Cu

__a------------------------------->a

=> \(3,3065-65a+64a=3,3065.90\%\)

=> 3,3065 - a = 2,97585

=> a = 0,33065

=> m_Zn = 0,33065.65 = 21,49225(g)