Câu hỏi của Cute Su

\(\dfrac{\left(x^2+6x+9\right)}{1-x}.\)\(\dfrac{\left(x-1^3\right)}{2\left(x+3\right)^3}\)\(=\dfrac{\left(x+3\right)^2}{-\left(x-1\right)}.\dfrac{\left(x-1\right)^3}{2\left(x+3\right)^3}\)\(=\dfrac{\left(x-1\right)^2}{-2\left(x+3\right)}\)\(=\dfrac{x^2-2x+1}{-2x-6}\)Câu trả lời: \(\dfrac{\left(x^2+6x+9\right)}{1-x}.\)\(\dfrac{\left(x-1^3\right)}{2\left(x+3\right)^3}\)\(=\dfrac{\left(x+3\right)^2}{-\left(x-1\right)}.\dfrac{\left(x-1\right)^3}{2\left(x+3\right)^3}\)\(=\dfrac{\left(x-1\right)^2}{-2\left(x+3\right)}\)\(=\dfrac{x^2-2x+1}{-2x-6}\)