Question

Answer 1

Lời giải:

a. $|\frac{1}{2}x-\frac{1}{6}|=\frac{1}{3}$

\(\Rightarrow \left[\begin{matrix} \frac{1}{2}x-\frac{1}{6}=\frac{1}{3}\\ \frac{1}{2}x-\frac{1}{6}=-\frac{1}{3}\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=1\\ x=\frac{-1}{3}\end{matrix}\right. \)

b.

$(4x^2-3)^3+8=0$

$\Leftrightarrow (4x^2-3)^3=-8=(-2)^3$
$\Leftrightarrow 4x^2-3=-2$

$\Leftrightarrow 4x^2=1$

$\Leftrightarrow x^2=\frac{1}{4}=(\frac{1}{2})^2=(\frac{-1}{2})^2$

$\Rightarrow x=\pm \frac{1}{2}$