\(a,=\dfrac{2x+4x+9}{2x+3}=\dfrac{3\left(2x+3\right)}{2x+3}=3\\ b,=\dfrac{2x-10}{x-5}=\dfrac{2\left(x-5\right)}{x-5}=2\\ c,\dfrac{12x+3x}{3\left(x-3y\right)}=\dfrac{15x}{3\left(x-3y\right)}=\dfrac{5x}{x-3y}\\ d,=\dfrac{2x^2-xy-xy-y^2+2y^2-x^2}{x-y}=\dfrac{x^2-2xy+y^2}{x-y}=\dfrac{\left(x-y\right)^2}{x-y}=x-y\)
Đúng 0
Bình luận (0)