\(=\dfrac{\left(3x+2\right)-4\left(3x-2\right)+3x-6}{\left(3x-2\right)\left(3x+2\right)}=\dfrac{3x+2-12x+8+3x-6}{\left(3x-2\right)\left(3x+2\right)}=\dfrac{-6x-4}{\left(3x-2\right)\left(3x+2\right)}=\dfrac{-2\left(3x+2\right)}{\left(3x-2\right)\left(3x+2\right)}=\dfrac{-2}{3x-2}\)