Question

Answer 1

Bài 1:
\(a,\dfrac{3x}{6y}=\dfrac{x}{2y};\dfrac{2x^2}{8x^3}=\dfrac{1}{4x};\dfrac{5xy}{10y}=\dfrac{x}{2}\)

\(b,\dfrac{x+2}{x^2-4}=\dfrac{x+2}{\left(x+2\right)\left(x-2\right)}=\dfrac{1}{x-2}\\ \dfrac{x-3}{x^2-9}=\dfrac{x-3}{\left(x-3\right)\left(x+3\right)}=\dfrac{1}{x+3}\\ \dfrac{x^2-1}{x+1}=\dfrac{\left(x-1\right)\left(x+1\right)}{x+1}=x-1\)