Question

Answer 1

\(R=\rho\dfrac{l}{S}\Rightarrow\rho=\dfrac{R.S}{l}=\dfrac{60.0,4.10^{-6}}{150}=1,6.10^{-7}\left(\Omega.m\right)\)

\(R_2=\rho\dfrac{l_2}{S_2}\Rightarrow S_2=\dfrac{\rho.l_2}{R_2}=\dfrac{1,6.10^{-7}.30}{30}=1,6.10^{-7}\left(m^2\right)\)

Answer 2

\(R1=p1\dfrac{l1}{S1}\Rightarrow p1=\dfrac{R1.S1}{l1}=\dfrac{60.0,4.10^{-6}}{150}=1,6.10^{-7}\left(\Omega m\right)\)

\(p1=p2=1,6.10^{-7}\Omega m\left(gt\right)\)

\(R2=p2\dfrac{l2}{S2}\Rightarrow S2=\dfrac{p2.l2}{R2}=\dfrac{1,6.10^{-7}.30}{30}=1,6.10^{-7}\left(m^2\right)\)