Question

 

Answer 1

\(R_{12}=\dfrac{R_1.R_2}{R_1+R_2}=\dfrac{30.30}{30+30}=15\left(\Omega\right)\)

\(R_{tđ}=R_{12}+R_3=15+15=30\left(\Omega\right)\)

\(I=I_{12}=I_3=\dfrac{U_{AB}}{R_{tđ}}=\dfrac{12}{30}=0,4\left(A\right)\)

\(U_{12}=U_1=U_2=I_{12}.R_{12}=0,4.15=6\left(V\right)\)

\(I_1=I_2=\dfrac{U_1}{R_1}=\dfrac{U_2}{R_2}=\dfrac{6}{30}=0,2\left(A\right)\)

Answer 2

R tương đương: 30(Ôm)

I1 =I2 =0,2(A)