Question

Answer 1

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Answer 2

3) ĐKXĐ: \(\left\{{}\begin{matrix}x\ge0\\x\ne4\\x\ne9\end{matrix}\right.\)

\(\dfrac{\sqrt{x}}{\sqrt{x}-3}=\dfrac{\sqrt{x}-1}{\sqrt{x}-2}\\ \Leftrightarrow\sqrt{x}\left(\sqrt{x}-2\right)=\left(\sqrt{x}-1\right)\left(\sqrt{x}-3\right)\\ \Leftrightarrow x-2\sqrt{x}=x-4\sqrt{x}+3\\ \Leftrightarrow2\sqrt{x}=3\\ \Leftrightarrow\sqrt{x}=\dfrac{3}{2}\\ \Leftrightarrow x=\dfrac{9}{4}\)