Question

Answer 1

\(a,M=\dfrac{\left(\sqrt{x}+3\right)^2}{\sqrt{x}+3}-\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\sqrt{x}-2}+\sqrt{x}\\ M=\sqrt{x}+3-\sqrt{x}-2+\sqrt{x}=\sqrt{x}+1\\ b,M=4\Leftrightarrow\sqrt{x}=3\Leftrightarrow x=9\left(tm\right)\\ c,M>2\Leftrightarrow\sqrt{x}\ge1\Leftrightarrow x\ge1\)