Question

Answer 1

\(A=6\sqrt{2}-\sqrt{2}+4\sqrt{2}=9\sqrt{2}\\ B=\dfrac{\left(2+\sqrt{3}\right)\left(\sqrt{3}+1\right)}{2}-\dfrac{\sqrt{3}\left(\sqrt{3}+2\right)}{\sqrt{3}}-\dfrac{\sqrt{3}}{2}\\ B=\dfrac{5+3\sqrt{3}}{2}-\dfrac{\sqrt{3}}{2}-\sqrt{3}-2\\ B=\dfrac{5+3\sqrt{3}-\sqrt{3}-2\sqrt{3}-4}{2}=\dfrac{1}{2}\\ C=\sin54^0\cdot\dfrac{\cos54^0}{\sin54^0}-\cos54^0=\cos54^0-\cos54^0=0\)