\(a,=20\sqrt{3}-12\sqrt{3}-10\sqrt{3}+6\sqrt{3}=4\sqrt{3}\\ b,=\sqrt{3}-1+\sqrt{\left(2-\sqrt{3}\right)^2}=\sqrt{3}-1+2-\sqrt{3}=1\\ c,=\dfrac{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}{\sqrt{x}-1}-\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\sqrt{x}+2}\\ =x+\sqrt{x}+1-\sqrt{x}+2=x+3\)